< PreviousMedan Magnetik1115.Induksi Magnetik di Sekitar Kawat Melingkar 8:0A4CB0A:0E0BF0=6<4;8=6:0@380;8@80@CA;8AB@8:38A4:8B0@:0E0BB4@A41CB0:0=B8<1C;8=3C:A8<06=4B8:F0=614A0@=F030?0B38B4=BC:0=34=60=<4=66C=0:0=?4@A0<00=8>B)0D0@B&4@70B8:0=!,"!0 0@0F0=6<C307C=BC:<4=678BC=614A0@8=3C:A8<06=4B8:38A4:8B0@:0E0B<4;8=6:0@14@0@CAF08BC34=60=<4=678BC=614A0@8=3C:A8<06=4B8:38?CA0B;8=6:0@0=B4@A41CBB8B8:& =3C:A8<06=4B8:38?CA0B:0E0B<4;8=6:0@30?0B38B4=BC:0=A4?4@B8?030?4=4=BC0=8=3C:A8<06=4B8:38A4:8B0@:0E0B;C@CA 8:0=30?4@70B8:0=D0@8014; ?030!,"!0 030;07A414A0@ H:0@4=00B460:;C@CA34=60=0@074;4<4= 0@600A0<034=60=:0@4=0:43C0=F014@78<?8B0=A478=66098:0D0@8014;D0@8014;B4@A41CB38<0AC::0=:430;0<?4@A0<00=8>B)0D0@B0:0=3830?0B<430=<06=4B8:38?CA0B;8=6:0@0=A41060814@8:CB A8= &4@;C=30?4@70B8:0=107E0?0=90=6:0E0BA0<034=60=:4;8;8=6:0E0BA478=6608=B46@0;<4<8;8:810B0A30@8=>;A0<?08 A478=660?4@A0<00=<4=9038 $ $ I %01!,!!- 914@;0:CC=BC:A0BC:0E0B<4;8=6:0@ 8:0B4@30?0B;8;8B0=:0E0B<4;8=6:0@<0:08=3C:A8<430=<06=4B8:38?CA0B;8=6:0@0=:0E0B<4=9038 $ I@07<430=<06=4B8:30?0B38B4=BC:0=34=60=0BC@0=B0=60=:0=0=A4?4@B8?030!,"!0 Gambar 5.11Induksi magnetik di pusat kawatmelingkar berarus.z0xyIrarId&4@70B8:0=60<10@14@8:CB 8:08=3C:A8<06=4B8:38?CA0B;8=6:0@0=14@0@CA;8AB@8: F0=614@90@890@8030;07B4=BC:0=8=3C:A8<06=4B8:38B8B8:&01IaP2I2IPaII!5!"0%;47:0@4=014=BC::0E0B70=F014@C?0 ;8=6:0@0=14A0@8=3C:A8<06=4B8:38030;07$ 34=60=0@07 <0AC:1830=61(4AC;B0=:C0B<430=<06=4B8:38B8B8:030;07$ I Contoh 5.3Tantanganuntuk AndaPerhatikan gambar berikut.Penghantar berbentuk duasetengah lingkaran konsentris,memiliki jari-jari a1 = 2 cm dana2 = 4 cm. Penghantar dialiri oleharus listrik I = 2 A.Tentukanlah besarinduksi magnetik total yang timbuldi titik pusat A.AIIa2a1 Mudah dan Aktif Belajar Fisika untuk Kelas XII1126.Induksi Magnetik di Pusat dan Ujung Solenoida# "# 030;07AC0BC;8;8B0=:0E0B?4=670=B0@F0=6?0=90=60B0C:C<?0@0=@0?0BF0=6<4=F4@C?08;8;8B0=?460AA4?4@B8F0=638BC=9C::0=?030!,"!0 ! 8:0:C<?0@0=?4=670=B0@388@8AA420@0<4<1C9C@<4;8=B0=60:0=3830?0B8@8A0=?4=0<?0=6A4?4@B8?030!,"!0 "!C<?0@0=?4=670=B0@F0=614@0@CA;8AB@8:0:0=<4=670A8;:0=60@8A<430=<06=4B8:34=60=?>;0A0<034=60=F0=63870A8;:0=>;47<06=4B10B0=6 8:0?0=90=6A>;4=>83030=B4@38@80B0A1C07;8;8B0=9C<;07;8;8B0=C=BC:A4B80?A0BC0=?0=90=6<4=9038"30=90@890@8:C<?0@0==F0 =3C:A8<06=4B8:38B8B8:&F0=6B4@;4B0:?030AC<1CA>;4=>83030=38A4101:0=>;474;4<4=A>;4=>830A4?0=90=6,030;07 A8= " & I 030;07AC3CB0=B0@0&30=,A478=660A8=2>A42A8=&& 2>B0=2>B0=2>A42,,, 4A0@=F08=3C:A8<06=4B8:38&>;47A4;C@C7?0=90=6:0E0BA>;4=>83034=60=<4=AC1AB8BCA8:0=70@60&30=,:430;0< %01!,!!- 9030;07 A8= " 2>A2>A " I 8:0A>;4=>830B4@A41CBA0=60B?0=90=6A478=660 H30= H14A0@8=3C:A8<06=4B8:38?CA0BA>;4=>830030;070B0C " I 4A0@8=3C:A8<06=4B8:38C9C=6A>;4=>83034=60= H30= H030;070B0C " I 0PdDxaPCAF rGambar 5.12(a) Solenoida yang dialiriarus listrik; (b) Penampang irisanmembujur solenoida.1)41C07A>;4=>830F0=6?0=90=6=F0 <30=90@890@8& <<4<8;8:8 ;8;8B0=A>;4=>830B4@A41CB380;8@80@CAA414A0@ 0*4=BC:0=8=3C:A8<06=4B8:38C9C=6A>;4=>8301 8:0A>;4=>83038@4=660=6:0=A478=660?0=90=6=F03C0:0;8A4<C;014@0?0:0714A0@=F08=3C:A8<06=4B8:38C9C=6A>;4=>830B4@A41CB!5!"0 =3C:A8<06=4B8:38C9C=6A>;4=>83038B4=BC:0=34=60=<4=66C=0:0= %01!,!!- 9 F08BC -1< < * $ " Contoh 5.4TokohHans Oersted(1777–1851)Hans Oersted adalah seorang ahliFisika berkebangsaan Denmark. Padatahun 1819 ia menemukanhubungan mendasar antarakemagnetan dan kelistrikan.Percobaannya menunjukkanterjadinya pembelokan pada jarumkompas ketika didekatkan dengankawat berarus. Fenomena ini dikenaldengan elektromagnetisme.Sumber: www.allautobiographies.comMedan Magnetik113PPPIIITes Kompetensi Subbab A%0)!*!-+!'$!+!,"3*3+!2('!- *4=BC:0=0@07<430=<06=4B8:38B8B8:&?03060<10@14@8:CB012 )41C07:0E0B;C@CA14@0@CA;8AB@8:38;4B0::0=<4<0=90=6?0300@07CB0@0A4;0B0= 8:00@CA<4=60;8@?030:0E0B30@8CB0@0:4A4;0B0=B4=BC:0=0@07<430=<06=4B8:38B8B8:&F0=614@90@0:&380B0A:0E0BB4@A41CB &03060<10@14@8:CB&4=670=B0@F0=614@0@CA;8AB@8:14@78<?8B0=30=A40@0734=60=AC<1C,?>A8B85*4=BC:0=0@07<430=<06=4B8:38B8B8:30=x–x+AzBIy+y – 8:08=3C:A8<06=4B8:38?CA0B:0E0B;8=6:0@0=F0=614@0@CA 30=14@90@890@8030;07B4=BC:0=8=3C:A8<06=4B8:38B8B8:&?03060<10@14@8:CB01)41C07:C<?0@0=:0E0B14@380<4B4@ 2<B4@38@80B0A ;8;8B0=*4=BC:0=14A0@0@CAF0=6<4=60;8@<4;0;C8:C<?0@0=8BC98:014A0@8=3C:A8<06=4B8:38?CA0B:C<?0@0=L I -1< 6I2Ia2a3a9IP2aIPKata Kunci•medan magnetik•garis gaya magnetik•fluks magnet•kaidah tangan kanan•hukum Biot-Savart•solenoida•toroida•induksi magnetikalingkaran arusBGambar 5.13Toroida yang dialiri arus listrik.1 8:0?0=90=6=F0389038:0=3C0:0;8A4<C;0 <A478=6608=3C:A8<06=4B8:38C9C=6A>;4=>830<4=9038 -1< < * $ " 6.Induksi Magnetik di Sumbu Toroida#&# 030;07:C<?0@0=F0=638;4=6:C=6:0=A478=660AC<1C=F0<4<14=BC:A41C07;8=6:0@0= 8:0B>@>830380;8@80@CA;8AB@8:0:0=B8<1C;60@8A60@8A<430=<06=4B8:14@14=BC:;8=6:0@0=3830;0<B>@>830B4@A41CB4A0@=F08=3C:A8<06=4B8:38B8B8:&F0=614@03038?CA0BAC<1CB>@>830030;07 "I $8;08"030;079C<;07;8;8B0=?4@A0BC0=:4;8;8=6;8=6:0@0=2aA478=660 %01!,!!- 9 30?0B38BC;8AA41060814@8:CB I !4B4@0=60=90@890@8B>@>830<9C<;07;8;8B0=Mudah dan Aktif Belajar Fisika untuk Kelas XII114B.Gaya Magnetik8!4;0A. =30B4;07<4=64B07C8107E098:0?4=670=B0@F0=6380;8@80@CA;8AB@8:30=38B4<?0B:0=38304@07<430=<06=4B8:?4=670=B0@B4@A41CB0:0=<4=60;0<860F0 0F0F0=6380;0<8?4=670=B0@B4@A41CB38=0<0:0=-!"( 0B0C- #&"(.&4@70B8:0=!,"!0 )4CB0A:0E0B34=60=?0=90=6F0=6380;8@80@CA;8AB@8: 38B4<?0B:0=3830;0<<430=<06=4B8:F0=60@07=F0B460:;C@CA<4=4<1CA1830=6:4@B0A!0E0BB4@A41CB0:0=<4;4=6:C=6:0@4=0?4=60@C760F0<06=4B8:4A0@=F060F0<06=4B8:F0=6380;0<8>;47:0E0B14@0@CA;8AB@8:3830;0<<430=<06=4B8:14@10=38=6;C@CA34=60=:C0B0@CA?0=90=6:0E0B?4=670=B0@:C0B<430=<06=4B8:30=A8=CAAC3CB0=B0@00@070@CA30=0@078=3C:A8<06=4B8:)420@0<0B4<0B8A14A0@60F0<06=4B8:30?0B38BC;8A:0=A41060814@8:CBA8= I !4B4@0=60= 60F0<06=4B8:$ :C0B0@CA;8AB@8:8=3C:A8<06=4B8:* AC3CBF0=63814=BC:>;47 34=60=?0=90=6:0E0B?4=670=B0@0;0<14=BC:D4:B>@ %01!,!!- 9 30?0B38BC;8AA41060814@8:CBLI 1.Menentukan Arah Gaya Magnetik=30B4;07<4=64B07C8107E098:0A4CB0A:0E0BF0=6<4<8;8:8?0=90=6380;8@80@CA;8AB@8:30=38B4<?0B:0=3830;0<<430=<06=4B8:0:0=B8<1C;60F0<06=4B8:4A0@=F060F0<06=4B8:?030:0E0B14@0@CA30?0B38B4=BC:0=34=60=<4=66C=0:0= %01!,!!- 9:0=B4B0?810608<0=0:0720@0<4=4=BC:0=0@0730@860F0<06=4B8:+=BC:<4=64B07C8=F0;0:C:0=;07*2(4(2!1(1(*!14@8:CB8=8Gambar 5.14Seutas kawat berarus I berada diruang yang dipengaruhi medanmagnetik B sehingga timbulgaya magnetik (F) pada kawattersebut.IFGambar 5.15Penghantar panjangberaruslistrik I di dalam medanmagnetik homogen B.IB Aktivitas Fisika 5.2Gaya MagnetikTujuan PercobaanMengamati gaya magnetikAlat-Alat Percobaan1.Aluminium foil4.Sebuah sakelar2.Sebuah magnet U5.Dua buah penjepit3.Sebuah bateraiLangkah-Langkah Percobaan1.Susunlah peralatan tersebut, seperti pada gambar berikut.pitaaluminiumpenjepitsakelar–+sebelumsakelar ditutup,pita aluminiumdalam keadaanmendatarFPsakelarQ–+Medan Magnetik1152.Tutuplah sakelar agar arus listrik mengalir melalui pita aluminium.3.Apakah yang terjadi dengan pita aluminium tersebut?4.Ubahlah polaritas dari baterai, kemudian amati yang terjadi pada pitaaluminium.5.Balikkan posisi kutub magnet U, kemudian amati yang terjadi pada pitaaluminium.6.Apakah kesimpulan Anda dari kegiatan ini?FBFIGambar 5.17Arah gaya magnetik sesuai dengankaidah tangan kanan.&4@70B8:0=!,"!0 8:0:0E0B?4=670=B0@F0=6380;8@80@CA;8AB@8: 38;4B0::0=3830;0<304@07<430=<06=4B8::0E0BB4@A41CB0:0=<4=60;0<860F0<06=4B8: F0=60@07=F0A4?4@B838BC=9C::0=?03060<10@B4@A41CBA478=660:0E0B0:0=<4;4=6:C=6:40B0A:0=B4B0?898:0?>;0@8B0A10B4@083810;8::0E0B0:0=<4;4=6:C=6:410E070:810B30@860F0<06=4B8:F0=60@07=F0:410E07468BC?C;070;=F098:00@078=3C:A8<06=4B8:38C10734=60=20@0<4=6C107?>A8A8<06=4B+0@0730@860F0<06=4B8:14@60=BC=6?0300@070@CA;8AB@8: 30=0@07<430=<06=4B8:0;0<<4=4=BC:0=0@0760F0<06=4B8:F0=6380;0<8:0E0B14@0@CA;8AB@8:3830;0<<430=<06=4B8:30?0B386C=0:0=:08307B0=60=:0=0=14@8:CB8=8 ( $ ("" "" ) '! "' " !$( & -" &$( "!")" ) & !"!"( " ) & !")" ) & &)' '(& & #&#"( $ (""!")" ) "& -!"( -" ! # +(&&)'?4@70B8:0=!,"!0 0380@0760F0<06=4B8:34=60=:08307B0=60=:0=0=<4=C=9C::0=081C90@8A4106080@070@CA 10@0760F0<06=4B8::4;C0@30@8B4;0?0:B0=60= 2AC3CB 030;07AC3CBF0=63814=BC:>;4781C90@8 34=60=90@8F0=6;08==F0Gambar 5.16Gaya magnetik yang dialami kawatpenghantar berarus listrik.SUBIon bermuatan dari Mataharimendekati Bumi dan masuk keatmosfer menuju daerah kutubpada umumnya dikatakan adanyapengaruh medan magnetik Bumi.Kadang-kadang kejadian inimenimbulkan fenomena yangdisebut aurora borealis atau cahayautara di daerah lintang utara.Charged ions approach the Earth fromthe Sun and enter the atmospheremainly near the poles, sometimescausing a phenomenon called theaurora borealis or northern lights innorthern latitudes.Informasiuntuk AndaInformation for You&4=670=B0@&'F0=6?0=90=6=F0 <30=8=3C:A8<06=4B8: *B4@;4B0:?0301830=630B0@:43C0=F0<4<14=BC:AC3CB HA0BCA0<0;08= 8:060F0<06=4B8: F0=614:4@90?030?4=670=B0@14A0@=F0 $34=60=0@07A4?4@B8?03060<10@B4=BC:0=14A0@30=0@070@CA;8AB@8:F0=6<4=60;8@?030?4=670=B0@8BC!5!"4=60=<4=66C=0:0=:08307B0=60=:0=0=38?4@>;470@070@CA30@8&:4')4AC0834=60= %01!,!!- 9 38?4@>;47A8= $ * <A8= H $ * < 038:C0B;8AB@8:030;07 <4=60;8@30@8&:4'PFQB Contoh 5.52.Gaya Magnetik pada Muatan yang Bergerak 8:0<C0B0=;8AB@8:%14@64@0:34=60=:424?0B0=*30;0<<430=<06=4B8:7><>64=0:0=B8<1C;60F0<06=4B8:?030<C0B0=B4@A41CB=30B4=BC<4=64B07C8107E07C1C=60=0=B0@0<C0B0=%30=:C0BSumber: Physics for Scientist and EngineersMudah dan Aktif Belajar Fisika untuk Kelas XII1160@CA 030;07% (A478=660 %01!,!!- 9 30?0B38=F0B0:0=<4=9038A8=% ( "8=B0A0=F0=638B4<?C7<C0B0=30;0<A4;0=6E0:BC(A0<034=60=14A0@:424?0B0=F08BC*(A478=66014A0@60F0<06=4B8:?030<C0B0=;8AB@8:F0=614@64@0:30?0B38=F0B0:0=34=60=?4@A0<00=A8= %* I !4B4@0=60=*14A0@:424?0B0=<C0B0=<A AC3CB0?8B0=B0@0:424?0B0=*30=<430=<06=4B8:&0@B8:4;14@<C0B0=F0=614@64@0:B460:;C@CAB4@7030?<430=<06=4B8:0:0=<4=60;0<860F0<06=4B8:F0=60@07=F0A4;0;CB460:;C@CAB4@7030?0@07:424?0B0=4=60=34<8:80=60F0<06=4B8:14@5C=6A8A41060860F0A4=B@8?4B0;A478=66064@0:?0@B8:4;<4@C?0:0=64@0:<4;8=6:0@14@0BC@0=A4?4@B8B0<?0:?030!,"!0 =60B5C=6A860F0A4=B@8?4B0;?03064@0:<4;8=6:0@4@30A0@:0= %01!,!!- 9C=BC: = 60F0<06=4B8:38=F0B0:0=34=60=?4@A0<00= %*I &0@B8:4;14@<C0B0=14@64@0:<4;8=6:0@:0@4=0<4=30?0B:0=60F0A4=B@8?4B0;F08BC60F0<06=4B8:#4=C@CB C:C< $4EB>=?03064@0:<4;8=6:0@14@0BC@0=14A0@=F060F030?0B38BC;8A:0=A41060814@8:CB !' %* *!&!*&%I !4B4@0=60=&90@890@8;8=B0A0=<8=3C:A8<06=4B8:*!<0AA0?0@B8:4;:6%<C0B0=?0@B8:4;*:424?0B0=;8=40@?0@B8:4;<A0608<0=0:0720@0<4=6C:C@<0AA0A41C07?0@B8:4;14@<C0B0=8>=+=BC:<4=6C:C@<0AA0A41C07?0@B8:4;14@<C0B0=8>=30?0B386C=0:0=A?4:B@>A:>?<0AA0&4@70B8:0=!,"!0 F0=6<4=68;CAB@0A8:0=A41C07A?4:B@>A:>?<0AA0&0@B8:4;14@<C0B0=8>=%3870A8;:0=>;47?4=670A8;8>=A4B4;07B8<1C;<430=;8AB@8:0:810B1430?>B4=A80; >=B4@A41CB<4=8=660;:0=B4<?0B):4<C380=<0AC::430;0<@C0=6F0=63830;0<=F0B4@30?0B<430=<06=4B8:7><>64=<4;0;C8A41C0724;07#430=<06=4B8:<4=F4101:0=8>=14@64@0:A4B4=607;8=6:0@0=34=60=90@890@8&3830;0<@C0=6B4@A41CB4A0@=F04=4@68:8=4B8:8>=?030A00B<C=2C;30=<C;0814@64@0:A0<034=60==>;:0=B4B0?8A4B4;078>=14@64@0:30=A0<?0838?>A8A80:78@=F08>=B4@A41CB<4<8;8:84=4@68:8=4B8:A414A0@ !* >=14@64@0:BGambar 5.18Gaya yang dialami muatanbergerak dalam medanmagnetik.RFvAGambar 5.19Pengukuran massa ionmenggunakan spektroskop massa.xr+qS–+BVMedan Magnetik117:0@4=0030=F0?4@C1070=?>B4=A80;3830;0<A?4:B@>A:>?A414A0@I%;47:0@4=0<C0B0=F0=614@64@0:030;07<C0B0=?>A8B858>=?4@C1070=4=4@68?>B4=A80;F0=6B4@90380:810B64@0:0=8>=B4@A41CB030;07$%4@30A0@:0= C:C<!4:4:0;0==4@68#4:0=8: $!*% %*!I %01!,!!- 9 030;07?4@A0<00=F0=6<4=F0B0:0=14A0@=F0:424?0B0=8>=3830;0<A?4:B@>A:>?4=60=<4=AC1AB8BCA8:0= %01!,!!- 9 :4 %01!,!!- 9 <0:00:0=38?4@>;47 !*&%!%&%! !&%I &4@70B8:0=:4<10;8!,"!0 , &<0:0 !,&%4=60=34<8:80=14A0@=F0<0AA08>=?0@B8:4;14@<C0B0=30?0B38=F0B0:0=34=60=?4@A0<00= %,!0B0C %&!I )41C07?0@B8:4;14@<C0B0= 14@03030;0<<430=<06=4B8:7><>64= I * 8:0:424?0B0=?0@B8:4;B460:;C@CA<430=<06=4B8:=F030=;8=B0A0=?0@B8:4;14@C?0;8=6:0@0=34=60=90@890@8 2<B4=BC:0=14A0@=F0<><4=BC<?0@B8:4;!5!"8:4B07C8% L I I * 2< <4=60=<4=66C=0:0= %01!,!!- 9 0:0=38?4@>;47 !*!*%%4=60=34<8:80=<><4=BC<?0@B8:4;030;07!*%L I I * < L I$A 038<><4=BC<?0@B8:4;B4@A41CB030;07 L I$AContoh 5.6Tantanganuntuk AndaSuatu partikel bermuatan 0,04 Cbergerak sejajar dengan kawatberarus listrik 10 A. Jika jarak antarapartikel dan kawat 5 cm, hitunglahberapa gaya yang dialami partikeltersebut?Mudah dan Aktif Belajar Fisika untuk Kelas XII118)41C07?0@B8:4;14@64@0:38A4:8B0@:0E0B14@0@CA;8AB@8:A4?4@B860<10@14@8:CB*4=BC:0=0@0760F0<06=4B8:F0=6380;0<8?0@B8:4;98:0?0@B8:4;B4@A41CB0?@>B>=14;4:B@>=!5!"@07<430=<06=4B8:380B0A:0E0B030;07:4;C0@1830=6:4@B0AA430=6:0=3810E07:0E0B<0AC:1830=6:4@B0A 0380@0760F0 38?4@>;4730@8:08307B0=60=:0=0=0+=BC:?0@B8:4;14@<C0B0=?>A8B85F08BC?@>B>=0@0760F0 <4=34:0B8:0E0B1+=BC:?0@B8:4;14@<C0B0==460B85F08BC4;4:B@>=0@0760F0 <4=90C78:0E0B3.Gaya Magnetik antara Dua Kawat Sejajar&0303C0:0E0B?4=670=B0@A49090@F0=6B4@?8A07A490C7380;8@80@CA;8AB@8: 30= &030!,"!0 ! A40@0734=60= 30=?030!,"!0 " 14@;0E0=0=0@0734=60= *4@=F0B0?030!,"!0 !:43C0:0E0BA0;8=6<4=34:0B0B0CB0@8:<4=0@8:A430=6:0=?030!,"!0 ":43C0:0E0BA0;8=6<4=90C70B0CB>;0:<4=>;0: =8<4=C=9C::0=107E00=B0@0:43C0:0E0BB8<1C;60F0<06=4B8:Gambar 5.20Dua buah penghantar lurussejajar dialiri oleh arus listrik.(a) I1 searah dengan I2.(b) I1 berlawanan arah dengan I2.garis medankarena I1I2garis medankarena I2PQB1B2F1F2agaris medankarena I2garis medankarena I1I1I2B1B2QPF1F2a01I1Contoh 5.74A0@=F060F0B8<10;10;8:0=B0@0:0E0BA0BC30=:0E0BF0=6;08=30?0B38BC@C=:0=A41060814@8:CB&030!,"!0 !0@CA;8AB@8: <4=8<1C;:0=8=3C:A8<06=4B8: 38B8B8:<0:014A0@ 030;07 &4=670=B0@14@0@CA 0:0=38?4=60@C78>;478=3C:A8<06=4B8: A478=660<4=60;0<860F0<06=4B8: A4AC0834=60=?4@A0<00= A8= A8= )4;0=9CB=F0?4=670=B0@14@0@CA <4=8<1C;:0=8=3C:A8<06=4B8: 38B8B8:4A0@=F0 BBIMedan Magnetik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ata Kunci•gaya magnetik•kaidah tangan kananContoh 5.8Tes Kompetensi Subbab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udah dan Aktif Belajar Fisika untuk Kelas XII120C.Aplikasi Gaya Magnetik&4=66C=00=60F0<06=4B8:30;0<:4783C?0=A470@870@80=B0@0;08=A41060814@8:CB1.Motor Listrik&4@=07:07=30<4<1>=6:0@38=0<>?030:8?0A0=68=0B0C38=0<>?030@038>($8=0<>F0=6030?0300;0BB4@A41CBA414=0@=F0030;07<>B>@F0=63864@0::0=>;47B4=060;8AB@8:#>B>@;8AB@8:030;070;0BF0=6<4=6C1074=4@68;8AB@8:<4=90384=4@68:8=4B8:64@0:):4<0<>B>@;8AB@8:A434@70=038BC=9C::0=?030!,"!0 IIporosarah putaranFBCBDFAkomutatorsikat karbonGambar 5.21Skema motor listrikGambar 5.22Skema galvanometerFaFbIIpivotUS!C<?0@0=38;4B0::0=380=B0@0<430=<06=4B8:)4AC0834=60=:08307B0=60=:0=0=:43C0:0E0B0:0=<4=60;0<860F0<06=4B8: F0=60@07=F0:40B0A30=:0E0B0:0=<4=60;0<860F0<06=4B8: F0=60@07=F0:410E07 038?030A8A8A8A8:C<?0@0=F0=614@;0E0=0=14:4@903C060F0F0=6A0<014A0@14@;0E0=0=0@0730=60@8A:4@90=F014@1430!43C060F0A4?4@B88=838A41CB #$ %;47:0@4=0030=F0:>?4;8=8:C<?0@0=0:0=14@?CB0@A40@07?CB0@0=90@C<90<&030?>A8A8D4@B8:0; H0@0760F0 0:0=A460@8A:4@90A478=660:>?4;A0<034=60==>;:0=B4B0?8:C<?0@0=B830:;0=6AC=614@74=B8A4101<0A87<4<8;8:8:424?0B0=0E0;)4;0=9CB=F03870A8;:0=;068:>?4;A478=660:C<?0@0=30?0BB4@CA14@?CB0@)4B4;07<4=4<?C7A4B4=607?CB0@0= H0@CA;8AB@8:F0=6<4;0;C8:0E0B30=14@C1070@07:810B=F0B8<1C;<><4=:>?4;F0=60@07=F014@;0E0=0=34=60=<><4=:>?4;F0=6?4@B0<0A478=660:C<?0@0=0:0=14@?CB0@:4<10;8:4?>A8A8A4<C;060@:C<?0@0=14@?CB0@B4@CA<4=4@CAA4B80?C9C=6:C<?0@0=387C1C=6:0=34=60=28=28=14;070B0C #!)((#&F0=6B4@1C0B30@8B4<1060)4B80?:><CB0B>@38B4:0=>;47A8:0BA8:0B:0@1>=!><CB0B>@8:CB14@?CB0@14@A0<0A0<034=60=:C<?0@0=B4B0?8A8:0BA8:0B:0@1>=B830:8:CB14@?CB0@B4B0??030B4<?0B=F0 0;8=8<4=60:810B:0=0@070@CAF0=6<4;0;C8:0E0B30=14@C1070@07A4B80?A4B4=607?CB0@0=A478=660:C<?0@0=30?0B14@?CB0@B4@CA<4=4@CA2.Galvanometer 0;D0=><4B4@030;07:><?>=4=30A0@30@80<?4@4<4B4@D>;B<4B4@30=>7<<4B4@):4<060;D0=><4B4@38BC=9C::0=?030!,"!0 0680=F0=6B4@?4=B8=630@80;0BC:C@8=8030;07A41C078=B814A8;C=0:F0=638;8;8B8:0E0BA478=660<4<14=BC::C<?0@0=F0=638;4B0::0=380=B0@0:CBC1CB0@030=A4;0B0=A41C07<06=4B!4B8:00@CA;8AB@8:<4=60;8@<4;0;C8:C<?0@0=A8A8A8A8:C<?0@0=F0=614@0303834:0B:CBC1CB0@030=:CBC1A4;0B0=<06=4B0:0=<4=60;0<860F0F0=614@;0E0=0=0@07A478=660:C<?0@0=0:0=14@?CB0@:0=B4B0?8Tugas Anda 5.2Anda mengenal kipas angin, mesincuci, dan motor penggerak mesinjahit. Alat-alat tersebut dihubungkandengan listrik arus AC. Carilah carakerjanya. Apakah cara kerjanya samadengan motor listrik yang dibahasberdasarkan Gambar 5.21?Next >