< PreviousGelombang Bunyi61Gambar 3.11Pola gelombang resonansisuatu pipa organa terbuka.nada dasar atauharmonik pertamanada atas pertama atauharmonik keduanada atas ketiga atauharmonik ketiga012132 &2522D2CA6BD2>2 2D2E B6<E6?C:H2?85:92C:=<2? $$ &2522D2C<65E2 2D2E B6<E6?C:H2?85:92C:=<2? $$&2522D2C<6 ? B6<E6?C:H2?85:92C:=<2? $ N(6B32?5:?82?7B6<E6?C:86=@>32?8H2?85:>:=:<:<@=@>E52B2A252A:A2@B82?2D6B3E<2C2>256?82?A6B32?5:?82?7B6<E6?C:86=@>32?8A25252G2:(6B32?5:?82?7B6<E6?C:H2?85:92C:=<2?@=69C6D:2AA@=286=@>32?8E?DE<A:A2@B82?2D6B3E<2252=29 $$$ N '34#/##0 9 H2?8>6BEA2<2?A6B32?5:?82?7B6<E6?C:5:<6?2=C63282:6-6/'3016..+52?>6BEA2<2?A6B32?5:?82?3:=2?82?3:=2?82?3E=2D*63E29A:A2@B82?2D6B3E<2A2?;2?8?H2 4>+6?DE<2??25252C2BH2?85:92C:=<2?A:A2D6BC63ED;:<246A2DB2>32D3E?H:5:E52B2 > C#7#$ :<6D29E:A2?;2?8A:A2 4> >46A2DB2>32D3E?H:$ > C 6?82?>6?88E?2<2? '34#/##0 97B6<E6?C:?25252C2B5:A6B@=69 2D2E >2<2 > >Contoh 3.6140cm2*H2B2DD6B;25:?H2?25252C2BH2:DE > C I >$*63E29A:A2@B82?2D6B3E<2H2?8A2?;2?8?H2 >52?7B6<E6?C:92B>@?:<?H236BDEBEDDEBED I52? I+6?DE<2?46A2DB2>32D3E?H:A252A:A2@B82?2D6BC63EDContoh 3.7Mudah dan Aktif Belajar Fisika untuk Kelas XII62b.Pipa Organa Tertutup(:A2@B82?2D6BDEDEA252=292=2DD:EA36BEA2D23E?8H2?8C2=29C2DEE;E?8A6?2>A2?8?H2D6BDEDEA*2=29C2DEE;E?8A:A2@B82?2D6BDEDEA>6?;25:C:>AE=86=@>32?8A252<@=@>E52B252?E;E?8=2:??H2H2?8D6B3E<2>6?;25:A6BED86=@>32?8(@=286=@>32?8H2?85:92C:=<2?D2>A2<C6A6BD:#/$#3 B6<E6?C:H2?85:92C:=<2?@=69A:A2@B82?2D6BDEDEA252=29C63282:36B:<ED &25252C2B 2D2E 7B6<E6?C:H2?85:92C:=<2? $$ &2522D2CA6BD2>2 2D2E 7B6<E6?C:H2?85:92C:=<2? $$ &2522D2C<65E2 2D2E 7B6<E6?C:H2?85:92C:=<2? $$&2522D2C<6N ? 2D2E B6<E6?C:H2?85:92C:=<2? $ N (6B32?5:?82?7B6<E6?C:H2?85:92C:=<2?@=69C6D:2AA@=286=@>32?8E?DE<A:A2@B82?2D6BDEDEA252=29 $$$ N '34#/##0 9 H2?8>6BEA2<2?A6B32?5:?82?7B6<E6?C:5:<6?2=C63282:6-6/'3016..+52?>6BEA2<2?A6B32?5:?82?3:=2?82?3:=2?82?82?;:=Gambar 3.12Pola gelombang resonansi padasuatu pipa organa tertutup.harmonik kedua134harmonik ketiga254harmonik pertama014#7#$%:C2=<2?? I52?? I 6?82?>6?88E?2<2? '34#/##0 95:A6B@=69? N?J N K $ I $ I $ $ > CGelombang Bunyi63*63E29A:A2@B82?2D6BDEDEA>6>:=:<:A2?;2?8 4>A23:=246A2DB2>32D3E?H:C22D:DE > CD6?DE<2?7B6<E6?C:?25252C2B ?2522D2CA6BD2>2 52??2522D2C<65E2 #7#$ :<6D29E: 4> >$ > C6B52C2B<2? '34#/##0 9 $ 5:A6B@=69M?25252C2B > C I >$M?2522D2CA6BD2>2 0 1 IM?2522D2C<65E2 0 1 IContoh 3.8*63E29A:A2@B82?2D6B3E<2 56?82?A2?;2?8 4>D6B;25: 3E29C:>AE=&252A:A2@B82?2D6BC63ED36B6C@?2?C:56?82?A:A2@B82?2D6BDEDEA 52?>6>36?DE< 3E29C:>AE=6B2A2A2?;2?8A:A2@B82?2H2?8D6BDEDEA#7#$)6C@?2?C:D6B;25:;:<2 C2>256?82? (2?;2?8A:A2@B82?2D6B3E<2 4>D6B;25: C:>AE=52? A6BED C69:?882 2D2E >2<2 4> 4> (252A:A2@B82?2D6BDEDEAD6B;25: C:>AE=52? A6BED C69:?882 2D2E >2<2 $56?82?>6?88E?2<2?CH2B2DB6C@?2?C:A2?;2?8A:A2@B82?2D6BDEDEA 52A2D5:9:DE?8 4> 4> $$ Contoh 3.9Pipa organa terbuka A dan pipaorgana tertutup sebelah B memilikipanjang yang sama. Perbandinganfrekuensi nada atas pertama antarapipa organa A dengan pipa organa Badalah ....a.1 : 1d.3 : 2b.2 : 1e.4 : 3c.2 : 3UMPTN 1995Pembahasan:Pipa organa terbuka:31, , , ....22APada nada atas pertama:AAAvvfxPipa organa tertutup:351, , , ....444BPada nada atas pertama:3443BB3 443BBBvvvfUntuk AB, diperoleh433 4AABBvffvJawaban: ePembahasan Soal3.Resonansi(6B:CD:G2:<ED36B86D2B?H2CE2DE36?52<2B6?225236?52=2:?H2?836B86D2B5:C63ED ! !*H2B2DD6B;25:?H2B6C@?2?C:252=297B6<E6?C:86D2B<65E236?5292BECC2>22D2E7B6<E6?C:36?52H2?8:<ED36B86D2BC2>256?82?<6=:A2D2?3:=2?82?3E=2D52B:7B6<E6?C:36?52H2?836B86D2B(6B92D:<2?5E24@?D@9A6B:CD:G2B6C@?2?C:36B:<ED:?:a.Resonansi pada Garputala":<2C63E2982BAED2=25:AE<E=82BAED2=2D6BC63ED36B86D2BC6A6BD:A252#/$#3 B6<E6?C:86=@>32?83E?H:H2?85:92C:=<2?36B82?DE?8A25236?DE<36C2B52?3292?=@82>82BAED2=2D6BC63ED#6D:<25:56<2D<2?A25282BAED2=2H2?8=2:?52?>6>:=:<:7B6<E6?C:3E?H:C2>282BAED2=2<65E22<2?:<ED36B86D2B(6B:CD:G2:<ED36B86D2B?H282BAED2=2H2?8<65E25:C63EDB6C@?2?C:Gambar 3.13Dua garputala yang memilikifrekuensi yang sama akanberesonansi.Mudah dan Aktif Belajar Fisika untuk Kelas XII64Aktivitas Fisika 3.3gelasairmineralparalongarputalaselangplastikgabusneonCepat Rambat BunyiTujuan PercobaanMengukur cepat rambat bunyi di udara.Alat-Alat Percobaan1.Garputala2.Lampu neon yang sudah tidak terpakai3.Botol air mineral 100 m4.Selang plastik berdiameter 1,5 cm dan panjang 2 m5.Pipa paralon berdiameter 3 cm dan panjang 1 m6.Penjepit7.Penggaris8.Gabus sebagai sumbatLangkah-Langkah Percobaan1.Rangkailah alat-alat tersebut seperti pada gambar.2.Isilah lampu neon dengan air sampai ketinggiankolom udara 5 cm.3.Getarkanlah garputala di atas lampu neon yangterbuka.4.Lakukan pemompaan terhadap air dari lampu neonagar air keluar melalui selang dengan botol air mineral secara perlahan-lahan.b.Resonansi pada Kolom Udara(6B92D:<2?#/$#3 H2?8>6>A6B=:92D<2?A6B:CD:G2B6C@?2?C:A252<@=@>E52B2":<2<@=@>E52B2H2?8D6B=6D2<5:2D2CA6B>E<22?2:B5:86D2B<2?56?82?>6?88E?2<2?C63E2982BAED2=2>@=6<E=>@=6<E=E52B25:52=2><@=@>E52B22<2?:<ED36B86D2B*H2B2DD6B;25:?H2B6C@?2?C:A252<@=@>E52B2252=29 D6A2DA252A6B>E<22?2:B92BECD6B36?DE<B2A2D2? C:>AE=86=@>32?8 A252E;E?8A6B>E<22?<@=@>E52B2>6BEA2<2?A6BED B6?882?82?86=@>32?8,?DE<>6?52A2D<2?B6C@?2?C:A2?;2?8<@=@>E52B25:2D2CA6B>E<22?92BEC5:E329E32952AE?7B6<E6?C:52?A2?;2?886=@>32?83E?H:?H2D6D2A)6C@?2?C:A6BD2>22<2?D6B;25:;:<2A2?;2?8<@=@>E52B25:2D2CA6B>E<22?2:B B6C@?2?C:<65E2 B6C@?2?C:<6D:8252?C6D6BEC?H2*2>292=?H256?82?86D2B2?E52B2A252A:A2@B82?2D6BDEDEA9E3E?82?A2?;2?8<@=@>E52B2D6B9252AA2?;2?886=@>32?83E?H:A252A6B:CD:G2B6C@?2?C:<@=2>E52B252A2D5:DE=:CC63282:36B:<ED N #6D6B2?82? A2?;2?8<@=@>E52B2<6N A2?;2?886=@>32?83E?H:":<27B6<E6?C:82BAED2=25:<6D29E:46A2DB2>32D86=@>32?83E?H:82BAED2=252A2D5:D6?DE<2?>6=2=E:A6BC2>22?$82B?5252A2D>6?82A=:<2C:<2?AB@C6CA6?8E<EB2?46A2DB2>32D3E?H:5:E52B236B52C2B<2?<@?C6AB6C@?2?C:3E?H:A252<@=@>E52B2=2<E<2?=292<D:F:D2C36B:<EDGambar 3.14Sebuah kolom udara di ataspermukaan air digetarkan olehsebuah garputala.Gelombang Bunyi656B52C2B<2?2<D:F:D2CD6BC63ED?522<2?>6?52A2D<2?52D2A2?;2?8<@=@>E52B2#6>E5:2?3282:>2?2<2942B2>6?89:DE?846A2DB2>32D3E?H:5:E52B2(6B92D:<2?<6>32=: '34#/##0 9 ? ":<2?52>6?89:DE?8C6=:C:9152?02<2?5:52A2D<2? N N N '=69<2B6?2A2?;2?886=@>32?8CE5295:<6D29E:?5252A2D>6?89:DE?846A2DB2>32D?H236B52C2B<2?A6BC2>22?$ N #6D6B2?82?$46A2DB2>32D3E?H:> CA2?;2?886=@>32?882BAED2=2>7B6<E6?C:82BAED2=2 INilai frekuensi setiap garputalasudah diketahui. Analoginyaseperti nilai fokus dari lensa.Ingatlah5.Berhentilah memompa air pada saat terdengar bunyi mendengung. Ukurpanjang kolom saat itu dan catat sebagai l1 (resonansi pertama) pada tabelpengamatan seperti berikut.6.Turunkan permukaan air dalam lampu neon sampai terdengar bunyimendengung lagi. Ukur panjang kolom saat itu dan catat sebagai l2(resonansi kedua) pada tabel pengamatan.7.Ulangi langkah tersebut sampai didapatkan l3, l4, dan seterusnya.Data Pengamatan Resonansi Udara untuk Percobaan Cepat Rambat UdaraResonansi ke–nPanjang Kolom Udara ( )1.2.3.............(25282>32BD2>A2<C63E29<@=@>E52B2H2?8A2?;2?8?H2E?DE<>6?892C:=<2?B6C@?2?C:<@=@>E52B2C642B2F6BD:<2=":<2<@=@>E52B2D6BA6?56<>6?892C:=<2?B6C@?2?C:C22D 4>D6?DE<2?7B6<E6?C:82BAED2=2+6?DE<2?AE=2A2?;2?8<@=@>E52B2A252B6C@?2?C:C6=2?;ED?H2 :<6D29E:46A2DB2>32D3E?H:5:E52B2$ > C#7#$ :<6D29E: 4> >$ > C(252A6B:CD:G2B6C@?2?C:A6BD2>252=2><@=@>E52B236B=2<E9E3E?82?36B:<ED 2D2E 4>4> >Contoh 3.10Mudah dan Aktif Belajar Fisika untuk Kelas XII66F.Energi Gelombang Bunyi+6=29?52<6D29E:329G286=@>32?8252=2986D2B2?H2?8>6B2>32D>6=2=E:I2DA6B2?D2B2>65:E>D6D2A:>65:E>?H2D:52<:<ED>6B2>32D 2=2>A6B2>32D2??H286=@>32?8>6>:?529<2?6?6B8:52B:C2DED6>A2D<6D6>A2D=2:? ?6B8:86=@>32?83E?H:H2?85:D:>3E=<2?52B:CE2B2A6C2G2D;6D!# ! 52A2D>6>6429<2?<242;6?56=2CE2DE32?8E?2? 2=D6BC63ED>6?E?;E<<2?329G26?6B8:86=@>32?83E?H:>6=2<E<2?A6B2>32D2? ?6B8:86=@>32?83E?H:52A2D5:D6?DE<2?52B:6?6B8:A@D6?C:2=>2<C:>E>86D2B2?<2B6?23E?H:>6BEA2<2?86=@>32?8=@?8:DE5:?2=92C:=A6B2>32D2?86D2B2?'=69<2B6?2:DE6?6B8:86=@>32?83E?H:52A2D5:?H2D2<2?56?82?H2:DEC63282:36B:<ED <2B6?2 Tes Kompetensi Subbab E'3,#-#0.#*&#.#/$6-6.#5+*#0 (252C6ED2C52G2:H2?8A2?;2?8?H2 >56?82?>2CC2 8A6B2>32D2?86=@>32?8DB2?F6BC2=H2?85:92C:=<2?>6>:=:<:<646A2D2? > C+6?DE<2?D682?82?52G2:D6BC63ED +2=:H2?8A2?;2?8?H2>5:D682?8<2?56?82?82H2 &(6B2>32D2?86=@>32?8DB2?CF6BC2=H2?85:92C:=<2?>6>:=:<:<646A2D2? > C+6?DE<2?>2CC2D2=:D6BC63ED E2ED2CD2=:H2?8C2>2A2?;2?85:D2B:<@=6982H2H2?8C2>2%2CC2D2=:A6BD2>2<2=:>2CC2D2=:<65E2+2=:A6BD2>25:86D2B<2?56?82?7B6<E6?C: IC652?8<2?D2=:<65E2 I":<2A2?;2?886=@>32?8A252D2=:A6BD2>24>D6?DE<2?A2?;2?886=@>32?8A252D2=:<65E2*63E2986=@>32?8C:?EC>6B2>32DA252D2=:H2?8A2?;2?8?H2 4>36B86B2<52B:C:>A2?82?>:?:>E><6>2<C:>E>*E2DED:D:<>6>6B=E<2?G2<DE C6<@?52=2>86B2<D6BC63ED+6?DE<2?2A6B:@5686=@>32?837B6<E6?C:86=@>32?8482H2D682?8D2=:;:<25:<6D29E:A2?;2?886=@>32?8 >52?>2CC2D2=: 8B2>*63E29A:A2@B82?2D6B3E<2A2?;2?8?H2 4>+6?DE<2?7B6<E6?C:?25252C2BH2?85:92C:=<2?A:A2D6BC63ED;:<246A2DB2>32D3E?H:5:E52B2 > C*63E29A:A2@B82?2D6BDEDEAA2?;2?8?H2 4>+6?DE<2??25252C2BH2?85:92C:=<2?A:A2:DE;:<246A2DB2>32D3E?H:5:E52B2 > C+6?DE<2?A2?;2?8>:?:>E>A:A2@B82?2D6B3E<2H2?836B6C@?2?C:56?82?82BAED2=2H2?836B86D2B56?82?7B6<E6?C: I;:<246A2DB2>32D3E?H:5:E52B2 > CKata Kunci•resonansi•Hukum Mersenne•pipa organa•Hukum I Bernoulli•Hukum II Bernoulli > C I >$"25:7B6<E6?C:82BAED2=2252=29 I(2?;2?8<@=@>E52B2A252B6C@?2?C:<65E2 52?<6D:82 52A2D5:D6?DE<2?56?82? '34#/##0 9 H2:DE 52?E?DE<B6C@?2?C:<65E2 252=29 > >"25:E?DE<B6C@?2?C:<6D:82 m >Gelombang Bunyi67Gambar 3.15Sumber bunyi berupa titik.Semakin jauh dari sumber bunyi,luas permukaan semakin besar.Pr1r22D2E >2<25:A6B@=69 N #6D6B2?82? >2CC2A2BD:<6=<8 2>A=:DE5@86=@>32?8>7B6<E6?C:86D2B I<@?CD2?D2A682C& >6B52C2B<2? '34#/##0 9 6?6B8:H2?85:A:?529<2?@=69CE2DE86=@>32?8C632?5:?856?82?<E25B2D2>A=:DE5@?H21.Intensitas Gelombang Bunyi!?D6?C:D2C86=@>32?83E?H:5:567:?:C:<2?C63282:;E>=296?6B8:3E?H:A6BC2DE2?G2<DEH2?8>6?6>3ECD682<=EBECCE2DE3:52?8A6BC2DE2?=E2C E3E?82?2?D2B252H2=E2C52?:?D6?C:D2C3E?H: >6>6?E9:A6BC2>22? N #6D6B2?82? :?D6?C:D2C86=@>32?83E?H:- >=E2CA6?2>A2?8> 52H286=@>32?83E?H:-*E>36B3E?H:36BEA2C63E29D:D:<C6A6BD:A252#/$#3 2<2?>6>2?42B<2?3E?H:<6C682=22B29BD:?H286=@>32?83E?H:>6B2>32D52=2>D:825:>6?C: 2=H2?8C2>2D6B;25:AE=2A25286=@>32?84292H2!?D6?C:D2C3E?H:A2523:52?8A6B>E<22?52=2>3@=2H2?8>6>:=:<:;2B:;2B: 2<2?>6>:=:<:=E2C 2?882AD:52<2526?6B8:3E?H:H2?89:=2?82D2ED6BC6B2AC6=2>2A6B2>32D2?!?D6?C:D2C3E?H:2<2?C6>2<:?<64:=;:<2;2B2<CE>36B3E?H:<6CE2DE3:52?8A6B>E<22?C6>2<:?;2E9(6?8EB2?82?:?D6?C:D2C3E?H:2<:32DA6BD2>3292?;2B2<52B:CE>36B3E?H:>6>6?E9:9E3E?82?36B:<ED N #6D6B2?82? ;2B2<CE>36B3E?H:<6A@C:C:3:52?8 > ;2B2<CE>36B3E?H:<6A@C:C:3:52?8 >6B52C2B<2? '34#/##0 9 52A2D5:?H2D2<2?329G2:?D6?C:D2C3E?H:36B32?5:?8D6B32=:<56?82?<E25B2D;2B2<CE>36B3E?H:D6BC63ED<63:52?8A6?56?82B2?2.Taraf Intensitas (TI)*6D:2A>2<9=E<5:2=2>C6>6CD2:?:>6>:=:<:32D2C:?D6?C:D2CA6?56?82B2?2D2C:?D6?C:D2C3E?H:H2?852A2D5:56?82BD6=:?82>2?EC:2252=29C63282:36B:<ED1 bel (B) = 10 desibel (dB)IngatlahTugas Anda 3.4Berapakah rasio intensitas bunyi 90dB terhadap intensitas bunyi 60 dB?Mudah dan Aktif Belajar Fisika untuk Kelas XII68+2B27:?D6?C:D2C3E?H:C63E29A6C2G2DA252;2B2< >252=29 56B2A2D2B27:?D6?C:D2C3E?H:A252;2B2< >#7#$ :<6D29E: > > 5!?D6?C:D2C3E?H:36B32?5:?8D6B32=:<56?82?<E25B2D;2B2< 56?82?>6?88E?2<2? '34#/##0 9 E?DE< 52? 5:A6B@=69 =@8 =@8 =@8=@8 Suatu gelombang gempa terasa diMalang dengan intensitas 6 × 105 W/m2.Sumber gempa berasal dari suatutempat yang berjarak 300 km dariMalang. Jika jarak antara Malang danSurabaya sebesar 100 km dan ketigatempat itu membentuk segitigasiku-siku dengan sudut siku-siku diMalang, maka intensitas gempa yangterasa di Surabaya adalah ....a.2 × 105 W/m2b.3 × 105 W/m2c.4,5 × 105 W/m2d.5,4 × 105 W/m2e.7,5 × 105 W/m2 UMPTN 1996Pembahasan:2221121122IrrIIIrr252530061010I= 5,4 × 105 W/m2Jawaban: dSurabayaMalangsumber gempa300 km100 kmContoh 3.11Pembahasan Soal2!?D6?C:D2CD6B<64:=H2?8>2C:952A2D>6?:>3E=<2?B2?8C2?82?A6?56?82B2?A252D6=:?82252=29C636C2B N G2DD > H2?85:C63EDC63282: " !"! 3!?D6?C:D2CD6B36C2BH2?8>2C:9>2>AE5:D6B:>2D6=:?82>2?EC:2D2?A2B2C2C2<:D252=29C636C2B G2DD > H2?85:C63ED"! "25:32D2CA6?56?82B2?D6B6?529252=29 N G2DD > 52?32D2C:?D6?C:D2CD6BD:?88:252=29 G2DD > +2B27:?D6?C:D2C C632?5:?856?82?=@82B:D>2A6B32?5:?82?2?D2B2:?D6?C:D2C3E?H:52?92B822>32?8:?D6?C:D2C3E?H:H2?8D6B56?82B52?>6>:=:<:C2DE2?56C:36=5*642B2>2D6>2D:C9E3E?82?2?D2B2 52? 5:DE=:C =@8 N #6D6B2?82? D2B27:?D6?C:D2C5 :?D6?C:D2C3E?H:- > N - > :?D6?C:D2C2>32?8A6?56?82B2?6B:<ED:?:52D2:?D6?C:D2C52?D2B27:?D6?C:D2C52B:3636B2A2CE>36B3E?H:>32?8A6?56?82B2? Q N >32?8B2C2C2<:D *:B:?6A252;2B2< > Q N $2=E=:?D2CB2>2: Q N(6B42<2A2?3:2C2A252;2B2< 4> Q N)25:@A6=2? Q N:C:<3:C:< Q N #$'. !?D6?C:D2C52?+2B27!?D6?C:D2C52B:636B2A2*E>36BE?H:05'04+5#4"/ 6/$'3608+ #3#(05'04+5#4&Sumber: College Physics, 1980Gelombang Bunyi69*63E29CE>36B3E?H:>6?892C:=<2?D2B27:?D6?C:D2CC636C2B 56B2A2D2B27:?D6?C:D2CH2?85:92C:=<2?;:<2D6B52A2D CE>36B3E?H:H2?8C2>252?36B3E?H:A252C22D36BC2>22?#7#$ :<6D29E: 5 ,?DE<C63E29CE>36B3E?H: =@8 =@8 ,?DE< 3E29CE>36B3E?H: Q >2<2+! =@8 =@8 =@8 5Contoh 3.12":<2D6B52A2DCE>36B3E?H:H2?8=63:952B:C2DED2B27:?D6?C:D2CD@D2=?H252A2D5:<6D29E:56?82?>6?88E?2<2?A6BC2>22?36B:<ED ? =@8 N #6D6B2?82? D2B27:?D6?C:D2C@=69 3E29CE>36B 32?H2<?H2CE>36B D2B27:?D6?C:D2C@=69 3E29CE>36B =@8 =@8 =@8 5 =@8 N 5"25:D2B27:?D6?C:D2C3E?H:A252;2B2< >252=29 5Kata Kunci•energi gelombang bunyi•intensitas gelombang•taraf intensitas•batas ambang pendengaran *63E29CE>36B3E?H:>6>:=:<:D2B27:?D6?C:D2CC636C2B 5":<2 3E29CE>36B3E?H:H2?8C2>236B3E?H:C6B6?D2<36B2A2D2B27:?D6?C:D2C3E?H:H2?85:92C:=<2? 6B2A2A6B32?5:?82?:?D6?C:D2C5E2CE>36B3E?H:;:<2D2B27:?D6?C:D2C?H2 5 *63E29CE>36B3E?H:D:D:<56?82?52H2 G2DD>6>2?42B<2?86=@>32?83E?H:36BEA286=@>32?8C76B:C3@=2+6?DE<2?D2B27:?D6?C:D2C3E?H:H2?85:56?82B@=69C6C6@B2?8A252;2B2< >6D6B52B:CE>36B3E?H:D6BC63ED N G2DD > *63E29CE>36B3E?H:>6>:=:<:D2B27:?D6?C:D2C36==":<2 3E29CE>36B3E?H:H2?8C2>236B3E?H:C642B2C6B6?D2<36B2A2<29D2B27:?D6?C:D2C3E?H:H2?85:92C:=<2?$5#0#4 *63E29CE>36B3E?H:>6>2?42B<2?6?6B8:<6C682=22B29A23:=2;2B2<A6?56?82BD6B9252ACE>36B3E?H:5:3E2D>6?;25:<2=:C6>E=236B2A2A6?8EB2?82?D2B27:?D6?C:D2C3E?H:H2?8D6B56?82BTes Kompetensi Subbab F'3,#-#0.#*&#.#/$6-6.#5+*#0Mudah dan Aktif Belajar Fisika untuk Kelas XII70Rangkuman 6=@>32?83E?H:252=2986=@>32?8=@?8:DE5:?2=H2?852A2D>6B2>32D52=2>>65:E>I2DA252D42:B52?82C 6A2DB2>32D3E?H:5:E52B236B82?DE?8A252;6?:CA2BD:<6=A6>36?DE<E52B2H2?85:?H2D2<2?56?82?$ C652?8<2?5:52=2>I2DA252D36B82?DE?8A252>@5E=EC.@E?852?>2CC2;6?:CI2D $52AE?5:52=2>I2D42:B36B82?DE?8A252>@5E=ECE=<52?>2CC2;6?:CI2D42:B $ +:?88:B6?529?2523E?H:36B82?DE?8A2527B6<E6?C:3E?H:#E2D3E?H:36B82?DE?8A2522>A=:DE5@86D2B2?E5:@C@?:<252=293E?H:H2?836B7B6<E6?C:2?D2B2 IC2>A2:56?82? I!?7B2C@?:<252=293E?H:H2?836B7B6<E6?C:5:32G29 IC652?8<2?E=DB2C@?:<252=293E?H:H2?836B7B6<E6?C:5:2D2C I 6=@>32?83E?H:52A2D>6?82=2>:AB@C6C5:CA6BC:B67B2<C:B67=6<C:5:7B2<C::?D6B76B6?C:52?A@=2B:C2C:!?D6B76B6?C:86=@>32?83E?H:D6B;25:;:<23652=:?D2C2?86=@>32?8?H2>6BEA2<2?<6=:A2D2?3:=2?82?3E=2D52B:C6D6?829A2?;2?886=@>32?83E?H: ! (6BC2>22?CEA6BA@C:C:86=@>32?83E?H: 4@C C:? &"" B6<E6?C:52??25252C2BA25252G2:5:?H2D2<2?56?82?A6BC2>22? C652?8<2?7B6<E6?C:?2522D2C<6 A25252G2:5:?H2D2<2?56?82?A6BC2>22? (252A:A2@B82?2D6B3E<27B6<E6?C:?2522D2C<6 5:?H2D2<2?56?82?A6BC2>22? $ C652?8<2?A252A:A2@B82?2D6BDEDEA7B6<E6?C:?2522D2C<6 5:?H2D2<2?56?82? $ E3E?82?A2?;2?8<@=@>E52B2D6B9252AA2?;2?886=@>32?83E?H:A252A6B:CD:G2B6C@?2?C:<@=@>E52B2252=29 2=2>A6B2>32D2??H286=@>32?83E?H:>6>:?529<2?6?6B8:C636C2B &56?82?& 252=292>A=:DE5@86=@>32?8 *6>2<:?;2E9;2B2<CE>36B3E?H:D6B9252AA6?56?82B:?D6?C:D2C3E?H:2<2?C6>2<:?<64:= !?D6?C:D2C3E?H:5:?H2D2<2?56?82?A6BC2>22? =@8 ":<2D6B52A2D 3E29CE>36B3E?H:D2B27:?D6?C:D2C3E?H:D@D2=?H25:?H2D2<2?56?82?A6BC2>22? ? =@8 Next >